pH
= pKa + log([proton acceptor]/[proton donor])
For acid,
pH = pKa + log([A-]/[HA])
For base,
pH = pKa + log([B]/[HB+])
Dissociation of acid:
* HA ----> H+ + A-
Ka = acid dissocation constant
= [H+][A-]/[HA]
Then,
Log Ka = log([H+][A-]/[HA])
= log([A-]/[HA]) + log[H+]
Then,
-log[H+] + log Ka = log([A-]/[HA])
Thus,
pH-pKa = log([A-]/[HA])
NB: